[4x -1/
(x+4) (4x² +1)]=
[a\
x+ 4]+
[bx+c\
4x² + 1]
after clear...
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Mathematics, 06.12.2019 04:31 Reddev
[4x -1/
(x+4) (4x² +1)]=
[a\
x+ 4]+
[bx+c\
4x² + 1]
after clearing fractions to decompose, the equation 4x - 1 =a(4x^2+1) + (bx+c)(x + 4) results. if x= -4 what is the value of a?
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