Mathematics, 05.12.2019 23:31 sierrabuckner397
Acylinder fits inside a square prism as shown. for every cross section, the ratio of the area of the circle to the area of the square is startfraction pi r squared over 4 r squared endfraction or startfraction pi over 4 endfraction.
a cylinder is inside of a square prism. the height of the cylinder is h and the radius is r. the base length of the pyramid is 2 r.
since the area of the circle is startfraction pi over 4 endfraction the area of the square, the volume of the cylinder equals
startfraction pi over 2 endfraction the volume of the prism or startfraction pi over 2 endfraction(2r)(h) or πrh.
startfraction pi over 2 endfraction the volume of the prism or startfraction pi over 2 endfraction(4r2)(h) or 2πrh.
startfraction pi over 4 endfraction the volume of the prism or startfraction pi over 4 endfraction(2r)(h) or startfraction pi over 4 endfractionr2h.
startfraction pi over 4 endfraction the volume of the prism or startfraction pi over 4 endfraction(4r2)(h) or pir2h.
Answers: 3
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Arectangular exercise mat has a perimeter of 36 feet the length of the mat is twich the width writeand solve an equation to determine the length in feet. of the mat then find the area in square feet of the mart
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Acylinder fits inside a square prism as shown. for every cross section, the ratio of the area of the...
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