Cyclist a leaves point x at 12 noon and travels at constant velocity in a straight path. cyclist b leaves point x at 2 p. m. travels the same path at constant velocity, and overtakes a at 4p. m. what was the speed of b?
(1) cyclist a weighs twice as much as cyclist b.
(2) when cyclist b overtook cyclist a, both had traveled 75 miles.

37.5 miles per hour

Step-by-step explanation:

The question might be trying to confuse the reader. Point (1) which states the difference in weight does not show any evidence on how it affects the speed of both cyclist. Point (2) show an important point where the distance traveled is 75 miles.

Cyclist B, who leave point X at 2pm overtook cyclist A at 4pm, showing that the time it took for B to overtook A is 2 hours

Speed = distance / time

= 75 miles / 2 hours

= 37.5 miles per hour

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

not sure but it may be b, as i said i'm not sure.