Which of the two functions below has the smallest minimum y-value?

f(x)=x^5-2
g(x)=3x^2+1

The correct option is B). f(x)

The minimum value for y belongs to f(x) at x=0 and f(0)=(-2)

Step-by-step explanation:

The given two functions are f(x)= and g(x)=

To find which function got minimum value for y :

For function f(x)=  

Using concept of Maxima and Minima,

Function : f(x)=

Differentiating the function we get,

f(x)=

Take f(x)=0

x=0

Therefore, f(x)=f(0)=0-2=(-2)

For function g(x)=

Using concept of Maxima and Minima,

Function : g(x)=

Differentiating the function we get,

g(x)=

Take g(x)=0

=0

x=0

Therefore, g(x)=g(0)=0+1=1

Thus, The minimum value for y belongs to f(x) at x=0 and f(0)=(-2)

The correct option is B). f(x)

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12