If log 2 = a, log 3 = b, and log 7 = c what is log 490 in terms of a, b and c and you can have integer coefficients

Answer is 2×c + log [10^{a} + 10^{b}] +a

Step-by-step explanation:

      log 2 = a ,log 3 = b ,  log 7 = c

      Using formula

      log d×e = log d + log e

      log d^{a} = a×log d

      log 5 =  log [10^{a} + 10^{b}]

      log 490 in terms of a , b and c and you can have integer coefficients

      log 490

       = log 7^{2}×5×2

       = 2×log 7 + log 5 + log 2

       = 2×c + log [10^{a} + 10^{b}] +a

       Answer is 2×c + log [10^{a} + 10^{b}] +a

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.