4x+2y=4,x-3y=15 how would u substitute this equation for both?

By using the substitution method, the equation solved and get the values of x and y as x = 3 and y = - 4

Step-by-step explanation:

Given equations are:

                   4 x + 2 y = 4         ……….(1)

                    x - 3 y = 15         …………(2)

Now, use the substitution method to solve the given two equations. Multiply equation 2 by 4 on both sides, we will get

                     4 x - 12 y = 60     ……..(3)

Now, subtract equation 1 from equation 3, we get

             (4 x + 2 y) - (4 x - 12 y) = 4 - 60

             14 y = - 56

             y = - 4

Hence, from the above equation, we get the value of y.

Now, we put the value of y in equation 2, we get

                    x - 3(-4) = 15

                    x + 12 = 15

                    x = 3

Hence, the value of x and y by using the substitution method as,

                              x = 3 and  y = - 4

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.