Marketing companies are interested in knowing the population percent of women who make the majority of household purchasing decisions. suppose a marketing company did do a survey. they randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. we are interested in the population proportion of households where women make the majority of the purchasing decisions. which distribution should you use for this problem?

Normal distribution with mean 0.6 and standard deviation 0.035

Step-by-step explanation:

It's a problem related to Population Proportion

In this, p′ = x / n where x represents the number of successes and n represents the sample size. The variable p′ is the sample proportion and serves as the point estimate for the true population proportion. q′ = 1 – p′

The variable p′ has a binomial distribution that can be approximated by the normal distribution

here, X is the number of “successes” where the woman makes the majority of the purchasing decisions for the household. P′ is the percentage of households sampled where the woman makes the majority of the purchasing decisions for the household.

x = 120

n = 200

p’ = 120/200 = 0.6

The sample proportion will follow the normal distribution. The mean of the distribution being p’ = 0.6

The standard deviation for the distribution is calculated as

Standard Deviation = √[(p’) x (1 – p’)/n]

Standard Deviation = √[(0.6) x (0.4)/200] = √0.0012

Standard Deviation = 0.035

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.