Website offers coupon of 15%.

what is the probability that at aya will be offered a coupon on at least one of the days she visits the website

0.62

Step-by-step explanation:

P(at least one coupon)

=1−P(no coupon all 6 days)

=1−(0.85^6)

≈1−0.377

≈0.623

The event is getting at least one coupon, and the complement is getting no coupon, being 0.85 and 0.15 respectively.  Simply raise the complement to the power of 6 (one for each day) and subtract from 1.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

a

step-by-step explanation:

the answer is a