Assume you are working with a standard deck of 52 cards. there are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits (clubs, diamonds, hearts, and spades). what is p(ace ∪ heart) if you draw one card?

answer:

1) 60% have a valid license, so 40% do not have a valid license

of the 60% with a valid license, 70% had no violations (100%-30%=70%)

70%*60%=0.7*0.6=0.42=42% had   no violations

of the 40% that had no valid license, 80% had no violations (100%-20%=80%)

80%*40%=0.8*0.4=0.32=32% had no violations

42%+32%=74% with no violations

2)what is the probability of drawing an ace or a heart

there are 4 aces and 13 hearts but one heart is an ace so you can't use the ace of hearts twice

p=(4+12)/52=16/52=4/13 or

p=(3+13)/52=16/52=4/13, or

p=(4/52)+(13//52)=(4+13-1)/52=16/52=4/13

step-by-step explanation: