Ab contains points (2, 1) and (-1, -8). what is the equation of the line parallel to ab that contains point (0, 2)?

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points that belong to the AB line:

We can find the slope:

By definition, if two lines are parallel then their slopes are equal. Thus, a line parallel to AB will have slope , then the equation will be of the form:

We substitute the given point and find b:

Finally, the equation is:

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !