2. compare ch3cl and ccl4. explain why one is polar and one is nonpolar. be sure to use
the term symmetry in your explanation.

Step-by-step explanation:

CH3Cl is polar while CCl4 is non polar.

When we consider whether something is polar or not we have to consider the following:

-Molecular symmetry

-Polar bonds (based on Electronegativity)

-Whether or not all the bonds are equal in magnitude

So for CCl4:

-All of the bonds are equal, in that all the electronegativity differences (delta EN) are the same.

-There are polar bonds as the delta EN between Cl (EN = 3.0) and C (EN=2.5) is 0.5 which means the bond is polar covalent

But when we look at the symmetry of the molecule (by drawing the lewis structure) there are no lone pairs, meaning that the molecule is symmetrical and therefore, it is non polar.

For CH3Cl:

-There are polar bonds here whether between C-H or C-Cl like above, both delta EN are greater than or equal to 0.5

-But, all of the bonds are not equal in strength. Cl (3.0) atoms have much higher electronegativity values than H (2.1) and there for they will "pull" the electrons closer and polarize the molecule. Therefore, the differences in bonds causes this molecule to be asymmetrical, and hence polar.

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4