Brandi jogged 2 1\2 miles in 30 minutes. sharma jogged 3 1\2 miles in 3\4 hour. who jogged at slower rate

The speed of Sharma is slower than the speed of Brandi

I.e ∵   4.67 miles per hour   5 miles per hour

      ∴  

Step-by-step explanation:

Given as :

The distance cover by Brandi = = 2 =

The Time taken by Brandi for jogging =   = 30 minutes = hour

Let the speed of Brandi = =

or,   =  }{\textrm   }" alt="D_1" />  }{\textrm   }" />

Or.   =

∴   = 5 miles per hour

Again

The distance cover by Sharma = = 3 =

The Time taken by Sharma for jogging =   = hour

Let the speed of Sharma = =

or,   =  }{\textrm   }" alt="D_2" />  }{\textrm   }" />

Or.   =

∴   = = 4.67 miles per hour

Now, ∵   4.67 miles per hour   5 miles per hour

         ∴  

So, Sharma jogged at slower late

Hence The speed of Sharma is slower than the speed of Brandi Answer

dont think so

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841