Danielle walked from her house to several locations in her town. the graph represents her distance from home after x hours.

a. how far from home was danielle after 1/2 hour?

b. what was danielle's speed between 0 and 1 hour?

c. what was danielle's speed between 1 and 2 hours?

d. what is the domain when the function is increasing?

e. what is the domain when the function is decreasing?

f. what is the domain when the function is constant?

!

According to the graph, after half hour, Danielle was 1 mile far from home.

To find the speed we have to apply the formula:

From and , Danielle went from to  . Replacing this values, we calculate the speed:

Therefore, the speed between 0 and 1 hour is 2 miles per hour.

The Danielle's speed between 1 and 2 hours is zero (). Because, according to the graph, during this time, Danielle didn't move, and without move, there's no speed.

The domain when the function is increasing refers to the increasing x intervals.

From the graph, this increasing interval is from 0 to 1 hours only, it's the only period of time when Danielle was increasing her position.

The parts of the decreasing domain are:

In the graph, you can see these decreasing intervals, which are characterized by a downwards direction of the line.

The parts where the function is constant:

Constant intervals, means no increase, no decrease, just an horizontal line.

1,918

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841