How to calulate the area of a square with a perimeter of 60 inches

Step-by-step explanation:

The formula of an area of a square:

s - side

The formula of a perimeter of a square:

s - side

We have a perimeter

Substitute:

            divide both sides by 4

Put it to the formula of an area of a square:

225 in.²

Step-by-step explanation: First, we want to find the length of one side. Since we know that a square has 4 sides and the perimeter is 60 inches, we can set up the following equation to find the length of one side.

Let's use l as our variable to represent length.

4l = 60

To get l by itself, we need to divide by 4 on the left side of the equation. Since we divided by 4 on the left side, we must also divide by 4 on the right side. On the left side, the 4's cancel and we are left with l. On the right side, we have 60 over 4 which simplifies to 15.

This means that a side of the square is 15 inches.

Now, we are asking ourselves what is the area of a square with a side length of 15 inches.

To find the area of a square, remember that a square is a type of rectangle so we can use the following formula.

Area = length × width

However, since the length and width of a square are always equal, we use a special version of this formula to find the area of a square.

Instead of area = length × width, we say that the area of a square equals side × side or S².

Since the sides of the square each have a length of 15 inches, the area of the square is equal to (15 in.)² or (15 in) (15 in) which equals 225 in.²

Therefore, the area of the square is 225 in.².

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.