M2 + 8m +7
m² + 5m + 6
m2 + 10m +9
m2 – 6m +8
m2 - 8m + 12
m2 + 11m + 24
how do i factor each trinomial ? ?

m² + 8m + 7 = (m + 1) (m + 7)

m² – 6m + 8 = (m – 2) (m – 4)

Step-by-step explanation:

If a trinomial ax² + bx + c is "factorable", you can use the AC method.

1. Multiply a and c.

2. Find factors of ac that add up to b.

3. Divide the factors by a and reduce.

4. The numerators are the constants, the denominators are the coefficients.

For example:

m² + 8m + 7

a = 1, b = 8, c = 7

1. ac = 1×7 = 7

2. Factors of 7 that add up to 8 are 1 and 7.

3. Divide by 1: 1/1 and 7/1

4. The factors are (m + 1) and (m + 7).

Therefore, m² + 8m + 7 = (m + 1) (m + 7).

Let's try one with a negative coefficient:

m² – 6m + 8

a = 1, b = -6, c = 8

1. ac = 1×8 = 8

2. Factors of 8 that add up to -6 are -2 and -4.

3. Divide by 1: -2/1 and -4/1

4. The factors are (m – 2) and (m – 4)

Therefore, m² – 6m + 8 = (m – 2) (m – 4).

You can check your answers by distributing.

i suppose it should be (y=2x-5)

step-by-step explanation: