Aline is parameterized by x=8+6t x = 8 + 6 t and y=3+2t (a) which of the following points are on the section of the line obtained by restricting t to nonnegative numbers (for each, enter y if the point is on the section, and n if not)? (−4,−1): (26 , 9) : (32,11): then, give one more point that is on the section of the line obtained by this restriction: (b) what are the endpoints of the line segment obtained by restricting t to − 5 ≤ t ≤ − 2 ? left endpoint: right endpoint:

We have the line parametrized by

Solving for t in each equation we have that

The point (a,b) lies in the line if when we replace a in the first equation and b in the second equation, the values of t coincide.

a)

1. (-4,-1)

Then, (-4,-1) lies in the line but no lies in the section of the line obtained by restricting t to nonnegative numbers.

2. (26,9)

Since t is positive then (26,9) lies in the line and lies in the section of the line obtained by restricting t to nonnegative numbers.

3. (32,11)

Since t is positive then (32,11) lies in the line and lies in the section of the line obtained by restricting t to nonnegative numbers.

4. If we take t=2 we obtain the point

(20,7) that lies in the section of the line obtained by restricting t to nonnegative numbers.

b)

When t=-5,

correspond to the point (-22,-7).

when t=-2

correspond to the point (-4,-1).

-22<-4 and -7<-1

then the left endpoint (-22,-7) and right endpoint (-4,-1)

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.

won't that be plagrisim thought?

step-by-step explanation: