Mathematics, 03.12.2019 10:31 meramera50
Nolan began a savings account three years ago. he invested $100 at a 2% interest rate according to the equation vn = 100(1.02)x, where vn is the value of his account after x years. anias started an account today. she invested $100 at a 2% interest rate according to the equation va = 100(1.02)x–3, where va is the value of her account. let’s say anias started saving at the same time nolan did, three years ago. approximately how much money would she have had to invest to have the same amount of money she has now?
$5.77
$90.24
$94.23
$106.12
Answers: 3
Mathematics, 21.06.2019 17:30, babygirl226
Select the correct answer from the drop-down menu. subtracting 3xy^2 from 8xy^2 gives the same result as the expression. [tex]3xy ^{2} - 8xy ^{2} [/tex][tex] { - 7xy}^{2} - {2xy}^{2} [/tex][tex] {7xy}^{2} - {2xy}^{2} [/tex]
Answers: 3
Nolan began a savings account three years ago. he invested $100 at a 2% interest rate according to t...
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