Need calculating this——i ran a test for a game, after developing a new laser for a ship named xavier, the target is a amber class dreadnought moving at 5500 mph and 3500 miles from xavier, the weapon needs to aim 1 mile ahead of the ship to hit it, however this new weapon has more velocity of 85k mph, while the original only 65k how far in front of the target do i need to aim in order to hit it, if this isn’t enough info let me know i might be able to give more. hope it’s possible

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation:

where is the gragh

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92