Let b = {(1, 3), (−2, −2)} and b' = {(−12, 0), (−4, 4)} be bases for r2, and let a = 0 2 3 4 be the matrix for t: r2 → r2 relative to b.
(a) find the transition matrix p from b' to b. p =
(b) use the matrices p and a to find [v]b and [t(v)]b, where [v]b' = [−2 4]t. [v]b = [t(v)]b =
(c) find p−1 and a' (the matrix for t relative to b'). p−1 = a' = (
(d) find [t(v)]b' two ways. [t(v)]b' = p−1[t(v)]b = [t(v)]b' = a'[v]b' =

126 maybe. sorry

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

hi how are you doing today? if you ever need just tell me

step-by-step explanation: