what is the approximate area of sector tsv?
round the answer to the nearest tenth.

a. 3.1 m^2

b. 2.3 m^2

c. 1.1 m^2

d. 0.5 m^2

C)  The area of the sector TSV  = 1.1 sq m.

Step-by-step explanation:

Here, the angle subtended by TSV at  the center of the circle  = 3 radians.

1 Radians = 57.2958°

So, 3 radians   = 3 x 57.2958 = 171.887 °

⇒The angle of the sector TSV = 171.887 °

Now, the angle of any sector of a circle with angle Ф at the center  

=  

Here, r  = 0.87 m

So, the area of the sector TSV  =  

or, the area of the sector TSV  = 1.13 sq m.

Now, rounding off the area to the nearest tenth ,we get:

The area of the sector TSV  = 1.1 sq m.

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: