The perimeter of a rectangle is twice the sum
of its length and its width. the perimeter is
40 meters and its length is 2 meters more
than twice its width.

The width of the given rectangle  =  6 m

The width of the rectangle  = 14 m

Step-by-step explanation:

Let us assume the width of the rectangle  = k

So, the length of the rectangle  =  2 + 2 ( The width)  = 2 +  2 k

Perimeter of the rectangle  = 40 meters

Now, PERIMETER OF THE RECTANGLE = 2(LENGTH + WIDTH)

or, 40 =  2 ( k + (2 +  2 k))

⇒ 2( 3  k + 2) = 40

or, 2(3 k) +  2(2) = 40

or, 6 k = 40 - 4  =  36

⇒ k = 36 / 6 = 6, or  k = 6

Hence, the width of the given rectangle  = k = 6 m

The width of the rectangle = 2 + 2 k =  2 + 2(6)  = 14 m

yes. we do proportions in probabilities.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.