Afarmer wants to fence a rectangular garden next to his house which forms the northern boundary. the fencingfor the southern boundary costs $6 per foot, and the fencing for the east and west sides costs $3 per foot. if hehas a budget of $120 for the project, what are the dimensions of the largest area the fence can enclose?

10 ft x 10 ft

Area = 100 ft^2

Step-by-step explanation:

Let 'S' be the length of the southern boundary fence and 'W' the length of the eastern and western sides of the fence.

The total area is given by:

The cost function is given by:

Replacing that relationship into the Area function and finding its derivate, we can find the value of 'S' for which the area is maximized when the derivate equals zero:

If S=10 then W =20 -10 = 10

Therefore, the largest area enclosed by the fence is:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47