What is the product? 2y/y-3 x 4y -12/2y+8

4y/(y+4)

Step-by-step explanation:

2y/(y-3) x [(4y -12) /(2y+8)]

To determine this, at first we have to break the parentheses. Since there is no matching values, we have to multiply the numerators and denominators.

[2y x (4y - 12)] / (y-3) x (2y + 8)

or, [(2y*4y) - (2y*12)]/[(y*2y) + (y*8) - (3*2y) - (3*8)]

(using algebraic equation)

or, (8y^2 - 24y)/(2y^2 + 8y - 6y - 24)

or, (8y^2 - 24y)/(2y^2 + 2y - 24)

or, 8y(y - 3)/2(y^2 + y - 12) (taking common)

or, 4y(y - 3)/(y^2 + 4y - 3y - 12)

or, 4y(y - 3)/[y(y + 4) - 3 (y + 4)] (Using factorization or Middle-Term factor)

or, 4y (y - 3)/(y + 4)(y - 3)

or, 4y/(y + 4) [as (y-3)/(y-3) = 1, we have dropped the part]

The answer is = 4y/(y+4)

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