At a large high school 40% of students walk to school, 32% of students have been late to school at least once, and 37.5% of students who walk to school have been late to school at least once. one student from the school will be selected at random. what is the probability that the student selected will be one who both walks to school and has been late to school at least once?

The probability that the student selected will be one who both walks to school and has been late to school at least once is = 0.15 or 15%

Step-by-step explanation:

From the question given, we find the probability that the student selected will be one who both walks to school and has been late to school at least once

Let,

B = Event that student walk to school

C = Event that student have been late to school at least once.

So,

P(B) = 0.40 , P(C) = 0.32

P(C | B) = 0.375

We apply the  multiplication rule,

P(B and C) = P(C | B) * P(B)

= 0.375 * 0.40

= 0.15 or 15%

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this