Mathematics, 30.11.2019 12:31 MOMMYDORA

Explain why converting from meters to centimeters uses a different exponent than converting from meters to millimeters.

Answers: 2

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Answer from: timithythaxton

Well, centimetre and millimetre both are same smaller unit than the metre.

So, to convert from metre to millimetre a centimetre, we have to multiply by a number greater than 1 .

1m = 100cm

1m = 1000mm

So multiply by 100 or 10^2 to convert from metre to centimetre .

And multiply by 1000 or 10^3 to convert from metre to millimetre .

Step-by-step explanation:

hope it helps

~Adrianna

Answer from: zafarm2oxgpmx

Converting from meter to centimeter uses a exponent of 2 and converting from meter to millimeter uses a exponent of 3

Solution:

The different units of length conversion charts are given as:

kilometre (km)

Hectometre (hm)

Decametre (dam)

Metre (m)

Decimetre (dm)

Centimetre (cm)

millimeter (m)

Converting from meters to centimeters:

From above listed units, we can observe meter is bigger unit than centimeter

So to convert from meter to centimeter, we have to move two times to reach centimeter in above listed units

So we have to multiply the value by 100 or 10 to power 2

1 meter = 100 cm

1 meter = 10^2 cm

So converting from meter to centimeter uses a exponent of 2

Converting from meter to millimeter:

Similarly using the above chart, we can say millimeter is smaller than meter.

So to convert from meter to millimeter, we have to move three times to reach millimeter in above listed units

In this, when we convert from meter to millimeter, we have to multiply the value by 1000

1 meter = 1000 millimeter

1 meter = 10^3 millimeter

So converting from meter to millimeter uses a exponent of 3

Answer from: Quest

The length is 23 and y because you add them together

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

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Explain why converting from meters to centimeters uses a different exponent than converting from met...