Mathematics, 30.11.2019 06:31 lisnel
The derivation in example 6.6.1 shows the taylor series for arctan(x) is valid for all x ∈ (−1,1). notice, however, that the series also converges when x = 1. assuming that arctan(x) is continuous, explain why the value of the series at x = 1 must necessarily be arctan(1). what interesting identity do we get in this case?
Answers: 1
Mathematics, 21.06.2019 17:00, sherlock19
If you apply the changes below to the absolute value parent function, f(x)=\x\, which of these is the equation of the new function? shift 2 units to the left shift 3 units down a. g(x)=\x-3\-2 b. g(x)= \x-2\-3 c. g(x)= \x+3\-2 d. g(x)= \x+2\-3
Answers: 1
Mathematics, 21.06.2019 21:10, samiam61
Which question is not a good survey question? a. don't you agree that the financial crisis is essentially over? 63on average, how many hours do you sleep per day? c. what is your opinion of educational funding this year? d. are you happy with the availability of electronic products in your state?
Answers: 2
The derivation in example 6.6.1 shows the taylor series for arctan(x) is valid for all x ∈ (−1,1). n...
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