The annual interest on an $20,000 investment exceeds the interest earned on a $4000 investment by $1320. the $20,000 is invested at a 0.6% higher rate of interest than the $4000. what is the interest rate of each investment? $20,000 is invested at what %$4,000 is invested at what %

"8.8%"

Step-by-step explanation:

Let x be the interest rate for the 20,000 and y for the 4,000

The problem says:

x20,000 = y4,000+1320 (1)

and

x = y+0.006 Substitute this value for x on equation (1)

(y+0.006)20,000 = y4,000+1320

20,000y+120 = y4,000+1320

16,000y = 1320

y = 0.0825 So the 4,000 are invested at 8.25%

And since x = y+0.006:

x = .0825+0.006 = 0.0885 or 8.8%. The 20,000 are invested at 8.8%

c. 4 and 1/2 pounds is the answer! : )

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.