The distance that a spring will stretch varies directly as the force applied to the spring. a force of 8080 pounds is needed to stretch a spring 88 inches. what force is required to stretch the spring 1919 inches? a nothing-pound force is required to stretch the spring 1919 inches.

176 199 pounds

Step-by-step explanation:

To answer this it is first useful to find the proportionality constant.

F= kx

8080 pounds = k.88 in

k = 91.81 pound/inch

So what force is required to stretch the spring to 1919 inches?

F = kx

  = 91.81 pound/inch * 1919 inches

  = 176 199 pounds

It is worth noting that this force seems rather large and the spring might have long reached its elastic limit

congruent segments

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i dont get the question

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