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Mathematics, 30.11.2019 01:31 ella9288

The inverse forms of the results in problem 49 in exercises 7.1 are ℒ−1 s − a (s − a)2 + b2 = eat cos bt and ℒ−1 b (s − a)2 + b2 = eat sin bt. use the laplace transform and these inverses to solve the given initial-value problem. y' + y = e−7t cos 6t, y(0) = 0y(t)=

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The inverse forms of the results in problem 49 in exercises 7.1 are ℒ−1 s − a (s − a)2 + b2 = eat co...

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