4.5.4 suppose a student wishes to minimize the objective function on a closed interval, but finds that it has only a single local maximum. where should the student look for the solution to the problem? choose the correct answer below. a. determine the value where the first derivative of the objective function is equal to 0. b. determine the value where the objective function is equal to 0. c. determine the value of each endpoint for the objective function. d. determine the value where the second derivative of the objective function is equal to 0. click to select your answer and then click check answer. all parts showing

Chemistry is a stone g subject hope you find the answer

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!