Apolymer is manufactured in a batch chemical process. viscosity measurements show that it is approximately normally distributed with a standard deviation of 20. a random sample of 42 batches has a mean viscosity of 759. construct a 99% confidence interval around the true population mean viscosity.

(751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

,

where =population standard deviation.

= sample mean

n= sample size

z* = Two-tailed critical z-value.

Given :  

n= 42

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it