Arestaurant chain sells 200,000 burritos each day when it charges $6.00 per burrito. for each $0.50 increase in price, the restaurant chain sells 10,000 less burritos. a. how much should the restaurant chain charge to maximize daily revenue? the restaurant chain should charge $ per burrito. b. what is the maximum daily revenue? b. the maximum daily revenue is $.

1280000

Step-by-step explanation:

Given that a restaurant chain sells 200,000 burritos each day when it charges $6.00 per burrito.

For each $0.50 increase in price, the restaurant chain sells 10,000 less burritos.

If x is the number of times price increased then sales would be

Revenue after price change

Now we can use calculus to find maximum

Let R(x) =

Equate first derivative to 0

we get x = 4

So maximum revenue is when 4 times price increased.

New price =

Sales =

Max revenue = .

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

29 mil

step-by-step explanation: