Fortyforty people purchase raffle tickets. three winning tickets are selected at random. if first prize is $50005000, second prize is $45004500, and third prize is $500500, in how many different ways can the prizes be awarded?

2193360

Step-by-step explanation:

Given : Total people = 40

Number of winning tickets = 3

When we choose m things from n things in an order then we use permutations to find the number of different ways to choose them.

Number of permutations of n things taking m at a time  :-

For r= 3  and n= 40 , we have

Hence, the number of different ways can the prizes be awarded = 2193360

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

answer: x=3 and y=4

step-by-step explanation: