Determine whether the relation r on the set of all real numbers is reflexive, symmetric, antisymmetric, and/or transitive, where (x, y) ∈ r if and only if:
(a) x + y = 0, (b) x = ±y, (c) x − y is a rational number, (d) x = 2y, (e) xy ≥ 0, (f) xy = 0, (g) x = 1, (h) x = 1 or y = 1.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

i need a diagram

step-by-step explanation:

no