Word problem on direct variation
moving object, the force acting on the object varies directly with the object's acceleration. when a force of 100 n acts on a certain object, the accelerati
object is 10 m/s. if the force is changed to 90 n, what will be the acceleration of the object?

acceleration would be 9 meters per second squared

Step-by-step explanation:

If quantity "A" varies directly with quantity "B", then we can write:

A = kB

Now, this problem says that force (f) varies directly with acceleration (a). So we can write:

f = ka

Given f = 100 and a = 10, so we substitute and find k (the proportionality constant). Shown below:

f = ka

100 = k(10)

k = 100/10

k = 10

So, we have

f = 10a

Now, force is 90, so what's the acceleration?

90 = 10a

a = 90/10

a = 9

So, the acceleration would be 9 meters per second squared