Engineers want to design seats in commercial aircraft so that they are wide enough to fit 9090% of all males. (accommodating 100% of males would require very wide seats that would be much tooexpensive.) men have hip breadths that are normally distributed with a mean of 14.5 in. and a standard deviation of 1.2 in. find upper p90. that is, find the hip breadth for men that separates the smallest 90% from the largest 10%.

the hip breadth for men that separates the smallest 90% from the largest 10% is p90__in.

(round to one decimal place as needed.)

Hip breadths less than or equal to 16.1 in. includes 90% of the males.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.5

Standard Deviation, σ = 1.2

We are given that the distribution of hip breadths is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.10.

P(X > x)  

Calculation the value from standard normal z table, we have,  

Hence, hip breadth of 16.1 in. separates the smallest 90% from the largest 10%.

That is hip breaths greater than 16.1 in. lies in the larger 10%.

fd

step-by-step explanation:

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