Abagel shop has onion bagels, poppy seed bagels, egg bagels, salty bagels. pumpernickel bagels, sesame seed bagels, raisin bagels, and plain bagels. how many ways are there to choose (a) six bagels? (b) a dozen bagels? (c) two dozen bagels? (d) a dozen bagels with at least one of each kind? (e) a dozen bagels with at least three egg bagels and no more than two salty bagels?

(a)262144

(b)68719476736  

(c)

(d)4096

(e)343

Step-by-step explanation:

Since there are 8 kinds of bagels, at each bagels we have 8 different ways to pick a bagels. With n bagels there would be ways to choose bagels.

(a) there are ways

(b) there are ways

(c) there are ways

(d) A dozen bagels with at least 1 of each kind would lock down the first 8 bagels to exactly be one of each kind, the rest (12 - 8 = 4 bagels) you can freely choose any of the 8

So there are ways

(e) A dozen with at least 3 egg bagels and at most 2 salty bagels would lock down the first 5 bagels to be that. Furthermore, of the rest (8 - 5 = 3 bagels) you can only have 7 option each.

So there are ways

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

t

step-by-step explanation:

ever thing time 1 is a multiply by 1 it get