Consider the following sample regressions for the linear, the quadratic, and the cubic models along with their respective r2 and adjusted r2.

linear quadratic cubic
intercept 9.66 10.00 10.06
x 2.66 2.75 1.83
x2 na −0.31 −0.33
x3 na na 0.26
r2 0.810 0.836 0.896
adjusted r2 0.809 0.833 0.895

pictureclick here for the excel data file

a.
predict y for x = 1 and 2 with each of the estimated models. (round intermediate calculations to 4 decimal places and final answers to 2 decimal places.)

linear
y-hat quadratic
y-hat cubic
y-hat
x = 1

x = 2

b. select the most appropriate model.

quadratic model
linear model
cubic model

15 batches are the most you can make

step-by-step explanation:

idk man good luck man

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

~