Auniversity claims its recent graduates earn an average annual salary of $50,000. you draw a random sample of 30 recent graduates and find that their average salary is $47,000, with a standard deviation of $5,000. what is the estimate of the standard error of the mean for this data?

$645.50

Step-by-step explanation:

The standard error of of the mean is given by :-

,

where n= sample size .

s= sample standard deviation.

Given : You draw a random sample of 30 recent graduates and find that their average salary is $47,000, with a standard deviation of $5,000.

i.e. n= 60

Samples standard deviation : s= $5,000

Then, the standard error of the mean for this data will be :-

[To the nearest cent]

Hence, the estimate of the standard error of the mean for this data = $645.50

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms