If c(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = c(x)/x. consider the cost function c(x) given below. c(x) = 2,000 + 160x + 4x3/2 (a) find the total cost at a production level of 1000 units. (round your answer to the nearest cent.) $ 288491.11 correct: your answer is correct. (b) find the average cost at a production level of 1000 units. (round your answer to the nearest cent.) $ 288.49 correct: your answer is correct. per unit (c) find the marginal cost at a production level of 1000 units. (round your answer to the nearest cent.) $ 349.73 correct: your answer is correct. per unit (d) find the production level that will minimize the average cost. (round your answer to the nearest whole number.) units (e) what is the minimum average cost? (round your answer to the nearest dollar.) $ per unit

2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.