The function f(t)=t^2+12t-18 represents a parabola. part a: rewrite the function in vertex form by completing the square. show your work. part b: determine the vertex and indicate whether its a maximum or minimum on the graph. how do you know? part c: determine the axis of symmetry

The function in vertex form is (refer to your other post I solved it there).
The general form of quadratic equations in vertex form is , where (h, k) is the vertex of the parabola.
Here, a = 1, h = -6 and k = -54
Therefore, the vertex is (-6, -54) and it is a maximum because a = 1 is postive.

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