80% of the trainees are female, while 20% are male. ninety percent of the females attended college; 78% of the males attended college. a management trainee is selected at random. based on this information, the probability that the person selected is a female who did not attend college is?

0.08

Step-by-step explanation:

Given : The probability that the person is female : P(F)=80%=0.080

The probability that the females attended college : P(A|F)=90%=0.90

Then, the probability that the females do not attended college :

Now using conditional probability formula :

We get,

Substitute the values , we get

Hence, the probability that the person selected is a female who did NOT attend college is 0.08 .

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752