If the length of one side of a square is triple and the length of an adjacent side is increased by 10, the resulting rectangle has an area that is 6 times the area of the original square. find the length of a side pf the original square.

10

Step-by-step explanation:

Given: If the length of one side of a square is triple and the length of an adjacent side is increased by .

To Find: If area is times the area of original square find length of a side of original square.

Solution:

Let the side of original square be

area of original square

when length of side is tripled,

new length of one side of square

length of other side is increased by 10 unit

new length of other side of square

new area of resulting rectangle

As area of resulting rectangle is 6 times the original square

as length cannot be zero

Hence the length of a side of original square is

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6