The center of a hyperbola is (−2,4) , and one vertex is (−2,7) . the slope of one of the asymptotes is 12 .

what is the equation of the hyperbola in standard form?

The equation of the hyperbola in standard form is

Step-by-step explanation:

Given:

Centre of the hyperbola=(−2,4)

one vertex of the hyperbola= (−2,7) .

slope of the asymptote = 12

To Find:

The equation of the hyperbola in standard form=?

Solution:

W know that the  standard form of hyper bola is

............................(1)

where

(h,k) is the centre

(x,y) is the vertex of the parabola

a is the length between the centre and the vertices of the hyperbola

b is  the distance perpendicular to the transverse axis from the vertex to the asymptotic line

Now the length of a is given by

a=|k-y|

a=|4-7|

a=|-3|

a=3

Also we know that,

Slope == 2

=>

=>

=>b=1.5

Now substituting the known values in equation(1)

Step-by-step explanation:

The standard form of a hyperbola centered at a point distinct from origin has the following form:

The distance between the center and the vertex is:

The value of the other semiaxis is:

The standard equation of the hyperbola is:

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: