Under certain water conditions the free chlorine in a swimming pool decomposes according to the law of inhibited decay. after shocking a pool, a pool boy, geoff, texted the water and found the amount of free chlorine to be 2.8 parts per million. twenty four hours later, geoff rested the water again and found the amount of free chlorine to be 2.4 ppm. what will be the reading after four days (that is 96 hours)? when chlorine level reaches 1.0 ppm, geoff must shock the pool again. how long can geoff go before he must shock the pool again?

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.