Arandstad/harris interactive survey reported that 25% of employees said their company isloyal to them (usa today, november 11, 2009). suppose 10 employees are selected randomlyand will be interviewed about company loyalty.
round your answers to four decimal places.
a. is the selection of ten employees a binomial experiment?
select: yes/no
explain.
the input in the box below will not be graded, but may be reviewed and considered by your instructor.
b. what is the probability that none of the 10 employees will say their company is loyal to them?
c. what is the probability that four of the 10 employees will say their company is loyal to them?
d. what is the probability that at least two of the 10 employees will say their company is loyal to them?

Which of the following is the equation that says that the product of a number and ten is equal to 20 percent of that number ? a) 10n= 2.0n b) 10+n=.20n c) n+ .20n=10 d) 10n=0.20n

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Each of the following data sets has a mean of x = 10. (i) 8 9 10 11 12 (ii) 7 9 10 11 13 (iii) 7 8 10 12 13 (a) without doing any computations, order the data sets according to increasing value of standard deviations. (i), (iii), (ii) (ii), (i), (iii) (iii), (i), (ii) (iii), (ii), (i) (i), (ii), (iii) (ii), (iii), (i) (b) why do you expect the difference in standard deviations between data sets (i) and (ii) to be greater than the difference in standard deviations between data sets (ii) and (iii)? hint: consider how much the data in the respective sets differ from the mean. the data change between data sets (i) and (ii) increased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). the data change between data sets (ii) and (iii) increased the squared difference îł(x - x)2 by more than data sets (i) and (ii). the data change between data sets (i) and (ii) decreased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). none of the above