Afrozen food company uses a machine that packages okra in six ounce portions. a sample of 54 packages of okra has a variance of 0.44. construct the 98% confidence interval to estimate the variance of the weights of the packages prepared by the machine. round your answers to two decimal places. lower endpoint and upper endpoint

Interval would be (0.29,0.58).

Step-by-step explanation:

Since we have given

n = Sample size = 54

Variance = 0.44

we need to find 98% confidence interval to estimate the variance.

So, we will use "Chi square distribution"

For this , we will find

df = n-1=54-1=53

Interval would be

similarly,

So, it becomes,

Hence, interval would be (0.29,0.58).

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)