According to data from the 2010 united states census, 43.1% of americans over the age of 65 were male.
suppose maria, a researcher, takes a random sample of 60 americans over the age of 65 and finds that 18 are male.
let p represent the sample proportion of americans over the age of 65 that were male.

what are the mean and standard deviation of the sampling distribution of p?

Step-by-step explanation:

The mean and standard deviation of the sampling distribution of p is given by :-

, where p= population proportion.

n= sample size.

Let p represent the sample proportion of Americans over the age of 65 that were male.

Given : The proportion of Americans over the age of 65 were male.

p= 43.1%=0.431

sample size : n= 60

Then, the mean and standard deviation of the sampling distribution of p will be :-

Hence, the mean and standard deviation of the sampling distribution of p :

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

the answer is d on edge

step-by-step explanation: