The ratio of the width to the length of a rectangle is 2: 3, respectively. answer each of the following. by what percent would the area of the rectangle change if the width of the rectangle is increased by 50% and the length is increased by the same number of units?

= 200%

Step-by-step explanation:

200%

Step-by-step explanation:

Length and breadth is in the ratio 2:3

Then, let length = 2x and breadth = 3x

Area of rectangle = l×b = 2x×3x = 6

Now if breadth is increased by 50% ,

our new breadth will be = 3x + 50%(3x)

                                       = 4.5x

And length is increased by same number of units, length = 2x+ 2x = 4x

New area = l×b = 4.5x × 4x

                        = 18

Percentage change in area = ×1000

                                           = ×100

                                           = 200%

Step-by-step explanation:

Let L & B be the original length & width of the rectangle then its area is

A0=LB

Now, the length & width both are increased by 50 % then new length & width become 1.5L & 1.5B then new area of rectangle

A1=1.5L×1.5B=2.25LB

Now, the percentage increase in the area of rectangle

=A1−A0A0×100 %

=2.25LB−LBLB×100 %

=125 %

hi im bob : l

step-by-step explanation:

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15