Two families go skiing on a saturday. one family purchases three adult lift tickets and four lift tickets for $188. another family purchases four adult lift tickets and five youth lift tickets for $244. let x represent the cost in dollars of one adult lift ticket and let y represent the cost in dollars of one youth lift ticket. solve the linear system to find the cost of one adult and one youth lift ticket.

using elimination to solve for x

9x +6y = 3*134    | Multiplying 1st equation by 3

-4x -6y = -2*146   | Multiplying 2nd equation by -2

   5x = 3*134 - 2*146

   5x = $110

    x = $22,  the cost of the youth ticket

Step-by-step explanation:This question Sets Up two equations with 2 unknowns        

Let x and y represent the cost of the youth and adult ticket respectively

Question states***

3x + 2y = $134    

2x + 3y = $146

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.